提交时间:2020-08-04 16:19:36

运行 ID: 5450

#include<bits/stdc++.h> using namespace std; int main(){ int x,a,b,ans=0; cin>>x>>a>>b; for (int dog=1; dog<=x/a; dog++) if (x-dog*a>0 && (x-dog*a)%b==0) ans++; cout<<ans<<endl; return 0; }