Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|---|
949 | 王兮 | 编程求1+1/2+1/3+...+1/n | C++ | Accepted | 100 | 0 MS | 252 KB | 178 | 2019-09-23 21:38:26 |
#include<iostream> int main() { int i=1; double sum=0; int n; scanf("%d",&n); while(i<=n) { sum=sum+(1.0/i); i=i+1; } printf("%.3lf",sum); return 0; }